# 1.find the equation of the line passing through (4,-3) parallel through 2x+54+y=02.if the area of triangle formed with the vertices (t,2t)(-2,6)(3,1) is 5 square units find if A =(-1,5)

2
by 012345
If the area of triangle formed with the vertices (t,2t)(-2,6)(3,1)is 5² units find t if A =(-5,5)
write , if A =(-1,5) then what will be the area? and now ur question is complete
i gave u the hinds...u can try
sry you are write A=(-1,5)
Equation is 2x+5y+4=0

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2015-11-29T22:31:20+05:30

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1.since line is parallel to 2x+54+y=0, so the equation will be 2x+y+c=0
Now point (4,-3) lie in this line,
so,c= -5
hence equation of line is 2x+y-5=0
2. we can use distance formula to find the length of sides and then
area= 1/2(base×height)
2015-11-30T17:43:51+05:30

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Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
1. equation given
2x-5y +4 =0
a=2 ,b=-5 , c=4
we know that equation of any line perpendicular to ax+by+c =0 is bx-ay +k =0
-5x -2y +k =0
passes through
(4 ,-3)
-5(4)-2(-7)+k=0
-20+6+k =0
k =14
required perpendicular line is -5x-2y+14 =0

2........
1/2 Ι x₁(y₂ - y₃)+x₂(y₃y₁)+x₃ (y₁y₂) Ι
(t,2t)        (-2,6)       (3,1)
x₁,y₁       x₂,y₂       x₃,y₃

1/2 l t (6-1) +(-2)(1-2)+3(2t-6) l =5
1/2 l 6t -1t -2 +4t +6t -18 l =5
1/2 l 15t -20 l =5
15t -20 =5 x 2
15t=10 +20
15t =30
t =30/15 =2
t =2