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2015-11-30T01:05:56+05:30

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Fluorine atoms have the smallest radii so it can be supposed that they have the greatest attraction of their nuclei to the shared pair of electrons which would thus make the covalent bond very hard to break indeed.But,
Such a strong nuclear attraction to the valence electrons , however means that inter-electronic repulsion will exist- electrons within the small F-F molecule will repel each other due to the valence electrons being closer to the other electrons (due to the stronger nuclear attraction) which will in turn weaken the F-F bond and result in it having a small bond enthalpy
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