# Two numbers are in the ratio 3:5.if each is increased by 10,the ratio between the new numbers so formed is 5:7.find the original numbers

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by rick1

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by rick1

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Initially, N1/N2 = 3x/5x

addind 10 on both, becomes,

(3x+10)/(5x+10)= 5/7

⇒21x+70=25x+50

⇒4x=20

⇒x=5

hope this is the best explanation :)

addind 10 on both, becomes,

(3x+10)/(5x+10)= 5/7

⇒21x+70=25x+50

⇒4x=20

⇒x=5

hope this is the best explanation :)

Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.

Given the ratio of two numbers = 3:5

let the numbers be 3x and 5x

the numbers increased by 10 = 3x+10 and 5x+10

the ratio is given as 5:7

Therefore 3x+10 : 5x+10 = 5 : 7

Product of means = Product of extremes

7(3x+10) = 5(5x+10)

21x +70 = 25x+50

70-10 = 25x- 21x

20 = 4x

4x = 20

x = 20/4

Therefore x = 5

The numbers are

3x = 3×5 = 15

5x = 5×5 = 25.

let the numbers be 3x and 5x

the numbers increased by 10 = 3x+10 and 5x+10

the ratio is given as 5:7

Therefore 3x+10 : 5x+10 = 5 : 7

Product of means = Product of extremes

7(3x+10) = 5(5x+10)

21x +70 = 25x+50

70-10 = 25x- 21x

20 = 4x

4x = 20

x = 20/4

Therefore x = 5

The numbers are

3x = 3×5 = 15

5x = 5×5 = 25.