# The perimeter of triangle is 288m and the ratio of sides is3:4:5 . Find the area of the triangle

2
by meenaljeirna

2015-12-01T19:30:16+05:30
A+b+c = 288 meters          a:b:c = 3:4:5

let a= 3x  b = 4 x    c = 5 x    where x  is some number
a+b+c  = x(3+4+5) = 12 x          So 12 x = 288 meters
x  =  24 meters
So a = 72 m  b = 96 m  c = 120 meters
If the sides of a triangle are in the ratio of 3 : 4 : 5, then it is  a right angle trianlgle.
Its area is  1/2 a b .    (a, b are smaller sides. c hypotenuse)
So Area  =  1/2  72 * 96  = 3456 meter²
IF the sides are not in a right angle triangle, the n  find s and use formula for area

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• qais
• Content Quality
2015-12-01T20:33:21+05:30
Let the side length be 3x , 4x and 5x
now ,a/q,
3x+ 4x+5x = 288
⇒12x= 288
⇒x= 24
so, length are 72 m, 96 m and 120 m
now we can see that, (120)² = (72)²+ (96)²
so. by Pythagoras theorem , this triangle is right angled triangle,
120 is the length of hypotenuse ,
area = 1/2 ×(96×72)
=3456 m²