# Abc is atriangle in which ab=ac if the bisectors of b&c meet ac and ab in d and e repectively prove that bd=ce

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so , ∠B = ∠C

now. D is on AC and E is on AB

and ∠DBC= 1/2 ∠B

and, ∠ECB =1/2 ∠C

so, ∠DBC = ∠ECB, (∵ ∠B=∠C)

now, Δ BDC is congruent to ΔEBC by SAS congruency

so, BD = CE ( cpct)