# A bag contains Rs 155 in the form of 1 rupee, 50 pause and 10 pause in the ratio 3:5:7. Find the number of each type of coins.

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let x be the no of coins

so,

3X+5X+7X=155 (the total no of coins equal to rs.155)

15x=155

x=155/15

x=10.3

so,

3X= 3*10.3=31(approx.)

5X=5*10.3=52(approx.)

7X=7*10.3=72(approx.)

THEREFORE THE BAG CONTAINS

THIRTY ONE(31) 1 RUPEES

FIFTY TWO(52) 50 PAISE

SEVENTY TWO(72) 10PASIE

and there after

31+52+72=155

AS 3×1×25=75

5×0.5×25=62.5

7×0.1×25=17.5

NOW,ADDING