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## Answers

Let α be 3 and β be -2.

sum=α+β=1

product=αβ=-6

Q.E=[x²-(sum)x+x]

=[x²-1x+(-6)

=x²-x-6

sum=α+β=1

product=αβ=-6

Q.E=[x²-(sum)x+x]

=[x²-1x+(-6)

=x²-x-6

Log in to add a comment

Let α be 3 and β be -2.

sum=α+β=1

product=αβ=-6

Q.E=[x²-(sum)x+x]

=[x²-1x+(-6)

=x²-x-6

sum=α+β=1

product=αβ=-6

Q.E=[x²-(sum)x+x]

=[x²-1x+(-6)

=x²-x-6