Answers

2015-12-03T18:35:45+05:30
If k, k-1, k+1  are three consecutive terms in an AP
⇒ r = 2k-1- (k)  =  2k+1-(2k-1)   [∵common ratio r is constant]
⇒k - 1 = 2k + 1 - 2k + 1
⇒k - 1 = 2
⇒k = 2+1
∴k =3

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