# A man buys two cycle at at Rs 900 .he sold one at the loss of 20%.other one at profit of 25%. on whole transaction he gain Rs 90. find the cost prize of each cycle.

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Let cost of one cycle be x and other cycle be y

so x + y = 900 ⇒ y = 900 - x

given (y × 125)/2 - ( x × 80)/100 = 90

((900 - x) × 125)/2 - ( x × 80)/100 = 90

solving x we get x = 505

so cost of cycles = rs 505 and 900 - 505 = rs 395

so x + y = 900 ⇒ y = 900 - x

given (y × 125)/2 - ( x × 80)/100 = 90

((900 - x) × 125)/2 - ( x × 80)/100 = 90

solving x we get x = 505

so cost of cycles = rs 505 and 900 - 505 = rs 395