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## Answers

= sin60[sin20.sin40.sin80]

=sqrt3 / 2 [sin20.sin(60-20).sin(60+20)]

=sqrt3 / 2 [sin 3(20)/4]

= sqrt3 / 2 [sin 60/4]

= sqrt3 / 2 [√3/2*4]

=sqrt3 /2 * sqrt3 /8

=3/16

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= sin60[sin20.sin40.sin80]

=sqrt3 / 2 [sin20.sin(60-20).sin(60+20)]

=sqrt3 / 2 [sin 3(20)/4]

= sqrt3 / 2 [sin 60/4]

= sqrt3 / 2 [√3/2*4]

=sqrt3 /2 * sqrt3 /8

=3/16