Answers

2015-12-10T23:47:34+05:30
Sin20. sin 40. sin60. sin80 
= sin60[sin20.sin40.sin80] 
=sqrt3 / 2 [sin20.sin(60-20).sin(60+20)] 
=sqrt3 / 2 [sin 3(20)/4] 
= sqrt3 / 2 [sin 60/4] 
= sqrt3 / 2 [√3/2*4] 
=sqrt3 /2 * sqrt3 /8 
=3/16 
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2015-12-11T18:18:15+05:30
−0.4651249 is the answer of this question
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