Answers

2015-12-13T10:14:15+05:30
X^2+5x+6=0
=>x^2+3x+2x+6=0
=>x(x+3)+2(x+3)=0
=>(x+3)(x+2)=0
=>(x+3)=0 or (x+2)=0
=>x=-3 or x=-2
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2015-12-13T10:58:41+05:30
X² + 5x + 6 = 0 
⇒x² + 2x + 3x + 6 = 0
⇒x(x + 2) + 3(x + 2) = 0
⇒(x+2)(x+3) = 0
⇒x+2 = 0   or   x+3 = 0
⇒x = -2      or   x = -3
∴The zeroes of the given polynomial are -2 and -3
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