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## Answers

X^2+5x+6=0

=>x^2+3x+2x+6=0

=>x(x+3)+2(x+3)=0

=>(x+3)(x+2)=0

=>(x+3)=0 or (x+2)=0

=>x=-3 or x=-2

=>x^2+3x+2x+6=0

=>x(x+3)+2(x+3)=0

=>(x+3)(x+2)=0

=>(x+3)=0 or (x+2)=0

=>x=-3 or x=-2

⇒x² + 2x + 3x + 6 = 0

⇒x(x + 2) + 3(x + 2) = 0

⇒(x+2)(x+3) = 0

⇒x+2 = 0 or x+3 = 0

⇒x = -2 or x = -3

∴The zeroes of the given polynomial are -2 and -3