# The side of square exceeds the side of another by 4cm .if the sum of the areas of the two sqare is 400 sq cm find the side of the sqare

2
by ranvir1

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by ranvir1

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a^2+(a+4)^2=400

a^2+a^2+8a+16=400

2a^2+8a-384

a^2+8a-192=0(dividing by 2)

by factorizing we will get 2 values 12 and -16 we neglect -16 as lenght cannot be negative therefore the a=12