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So given height of a right angle triangle = a - b

given base of a right angle triangle = a +b

use Pythagoras theorem we get

hypotenuse = √{(a - b)² + (a + b)²}

= √{2(a² + b²)}

so sin θ=

(a - b)/√{2(a² + b²)}

given base of a right angle triangle = a +b

use Pythagoras theorem we get

hypotenuse = √{(a - b)² + (a + b)²}

= √{2(a² + b²)}

so sin θ=

(a - b)/√{2(a² + b²)}