# A man buys bananas at 6 for ` 5 and an equal number at ` 15 per dozen. He mixes the two lots and sells them at ` 14 per dozen. Find his gain or loss percent, in the transaction

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So the cost = ( n/5 ) * 6 = 6n/5

He gets n again at 15 per dozen

=> Cost = 15n/12 = 5n/4

=> Total CP = 6n/5 + 5n/4 = 49n/20

He mixes the two and selles them at 14

=> Selling Price = ((n + n ) /12 ) * 14

= 14n/6 = 7n/3

Profit or loss = SP - CP = 7n/3 - 49n/20

= n ( 7/3 - 49/20 )

Do the rest ...

If it comes negative , then he incurred loss . If it comes positive , then it was a profit.

You can find the percentage by

( SP - CP ) / CP * 100