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2015-12-19T15:18:27+05:30

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A number, suppose x, is increased by 20% and then decreased by 20%.

It is increased by 20%.

20% of x = x*20% = x* \frac{20}{100}

= \frac{20x}{100}


= \frac{x}{5}


After increasing by 20%, the total amount is =

=
x+20% of x
                          

= x+\frac{x}{5}
                          

= \frac{5x+x}{5}
                           

= \frac{6x}{5}
 


Now, number is \frac{6x}{5}.

 \frac{6x}{5} will be decreased by 20% of  \frac{6x}{5} .


20% of  \frac{6x}{5} = 20% of  \frac{6x}{5}


=  \frac{6x}{5}*20%

= 6x*4%


= 24x%


=  \frac{24x}{100}


∴  \frac{6x}{25}


After decreasing by 20%, the total amount is =

=  \frac{6x}{5}-\frac{6x}{25}


=  \frac{5(6x)-6x}{25}


=  \frac{30x-6x}{25}


=  \frac{24x}{25}

So, net decrease amount is...

x- \frac{24x}{25}

 \frac{25x-24x}{25}


 \frac{x}{25}

The net decrease percentage = 

= 
 \frac{x}{25}*100%


x*4%


4%

ANSWER: The net decrease percentage is 4%.




0
Great job !
I think I should delete the first answer
Hmm..
awsme answer......
good!