Answers

2015-12-18T12:38:33+05:30
A cube has 6 faces . He only excludes the base ( bottom face . ) .The area of each face = s^2 where s is edge length . So total area Aditya must cover = 5 * ( 1.5 ) ^2 square metres . 1m = 100 cm => 1cm = 0.01m => 25cm = 0.25m = side length of each tile . So total no. of tiles required = ( total area to be covered ) / ( area of each tile ) = ( 5 * ( 1.5 ) ^ 2 ) / ( 0.25 ) ^2 Cost of a dozen ( 12 ) tiles = 480 => cost of each = 480/12 = 40 Now total cost = ( Total no. of tiles ) * ( cost of each tile ) = ( 5 * ( 1.5 ) ^ 2 ) * 40 / ( 0.25 ) ^2 = ( 5 * 2.25 * 40 ) / ( 0.0625 ) Multiply 10000 to numerator and denominator to make it easier & clearer = ( 5 * 225 * 4000) / 625 = 225 * 400/25 = 45*400/5 = 9*400 = ₹3600
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