# The cost of 3 tables and 8 chairs is RS.4350 and the cost of 2 tables and 5 chairs is Rs.2800.Find the cost of one table and one chair separately?

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by noho

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by noho

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8x+3y=4350 and

5x+2y=2800=>y=(2800-5x)/2

Putting value of y in first equation

8x+3((2800-5x)/2)=4350

Multiplying by 2

16x+3(2800-5x)=8700

16x+8400-15x=8700

X=300

Again

5x+2y=2800

5(300)+2y=2800

1500+2y=2800

2y=1300

y=650

Therefore, cost of one table is 650 rs and one chair is 300 rs.

Let the cost of a chair be y.

A/C

3x+8y=4350 ------------(1) and

2x+5y=2800-------------(2)

Multiply (1) with 2

Multiply (2) with 3

then the equation becomes:

6x+16y=8700

6x+15y=8400

By elimination method the equation becomes:

y=300 substitute in equation 1

⇒3x+8(300)=4350

⇒3x+2400=4350

⇒3x=4350-2400

⇒3x=1950

⇒x=1950/3

⇒x=650

∴ x = 650, y= 300

∴The cost of a table is Rs. 650 and the cost of a chair is Rs.300

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Yours, Jahnavi