# A car starts from rest and attains a velocity of 10m/s in 40s. The driver applies breaks and slows down the car to 5m/s in 10s. Find the acceleration of the car in both the cases.

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u = 0 m/s

v = 10 m/s

t = 40 sec

a = ?

v = u+at

10 = 0+a*40

10 = 40a

therefore a=10/40

ans=0.25 m/s²

In second case,

u = 10 m/s

v = 5 m/s

t = 10 sec

v = u+at

5 = 10 + a10

a10 = -5

a = -5/10

therefore ans. = -0.5 m/s²

The Brainliest Answer!

u = 0

v = 10 m/s

t = 40 s

a = v - u/t

= (10 - 0)/40

= 10/40

= 0.25 m/s²

In second case:

u = 10 m/s

v = 5 m/s

t = 10 s

a = (5 - 10)/10

= -5/10

= -0.5 m/s²