An Engineer standing on the ground level at certain distance from the tower observed that angle of elevation is 60°. By moving further distance of 30 m away from his original position he observed that the angle of elevation is 30°. Help him to find the height of the tower



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Initially, Let the height of tower is h
 and engineer is at x m distance from the tower
tan60° = h/x
⇒h =x√3
after 30 m away from the tower
tan30 = h/(x+30)
⇒1/√3 =(x√3)/(x+30)
⇒2x =30
⇒x =15
so height of the tower = 15√3 m