Answers

2015-12-26T17:55:59+05:30
X2+7x+12
x2+4x+3x+12
x(x+4)+3(x+4)
(x+4)(x+3)
x=-4,-3
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2015-12-26T20:28:47+05:30
X² + 7x + 12 = 0
⇒x² + 4x + 3x +12 = 0
⇒x(x+4) + 3(x+4) = 0
⇒(x+4)(x+3) = 0
⇒x+4 = 0    or    x+3 = 0
⇒x =-4        or    x =-3
 ∴x = -4, -3 
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