# Sanjiv has ruppes3.10 in10 paisa and 25 paisa coins.if the 10 paisa coins exceed the number of 25 paisa coins by three, how many coins of each does he have!

2
by sanju0147

• qais
• Content Quality
2015-12-27T08:34:48+05:30

### This Is a Certified Answer

Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
Number of 10 paisa coin = x
number of 25 paisa coin =y
A/q,
x - y = 3
⇒x = 3 +y
and, 10x + 25y = 310
⇒ 10 ( 3 +y) + 25y = 310
⇒30 +10y + 25y = 310
⇒35 y= 280
⇒y =8 and x = 11
there are 11 coins of 10 paisa and 8 coins of 25 paisa
2015-12-28T15:46:05+05:30
Let x be the number of 10 paise coins and y be the number of 25 paise coins.
given,
10x+25y=310                     [3.10=310 paise]
divide the eqn by 5,
we get,
2x+5y=62-------------------(1)
then, x-y=3
multiply the eqn by 2,we get,
2x-2y=6---------------------(2)
(1)-(2)======>7y=56
thus, y=8.
putting y=8 in (1)
2x=62-40
=22
thus x=11.
ans:there are 11 10 paise coins and 8 25 paise coins