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## Answers

lim n→∞ an = 0.

Proof.

Let ϵ > 0.

Then for n ≥ n∗ = 2+ 1. 2ϵ

we have 2n−3 ≥ 4+1. ϵ. −3 > 1. ϵ. > 0,

so 0 < 1. 2n−3.

HOPE THIS WILL HELP YOU

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lim n→∞ an = 0.

Proof.

Let ϵ > 0.

Then for n ≥ n∗ = 2+ 1. 2ϵ

we have 2n−3 ≥ 4+1. ϵ. −3 > 1. ϵ. > 0,

so 0 < 1. 2n−3.

HOPE THIS WILL HELP YOU