Answers

  • Brainly User
2014-02-18T15:51:19+05:30
Let x be the fathers present age.
therefore sons present age = 2x/7
after 5yrs
fathers age = x+5
sons age = 2x/7 +5
now sons age = 37% of fathers
=> 2x/7 + 5 = (x+5)37/100
=>(2x+ 35)/7 = (37x + 185)/100
=>100(2x+35) = 7(37x+185)
=>200x +3500 = 259x + 1295
=> 59x = 2205
=> x= 37.37 yrs
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2014-02-19T12:59:44+05:30
Let present ages of father be x and of son is y years
x/y = 7/2 , 2x = 7y , y = 2x/7
(y+5) = 37/100 * (x+5)
(2x/7 + 5) = 37/100 * (x+5)
(2x + 35) / 7 = (37x + 185) / 100
200x + 3500 = 259x + 1295
259x - 250x = 3500-1295
59x = 2205
x = 37.37 years
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