# o Three consecutive natural numbers ae such that the square of the middle number exceeds the difference of the squares of the other two numbers by 60

1
by vasistsanjana

2016-01-02T13:54:09+05:30

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Question: Three consecutive natural numbers are such that the square of the middle number exceeds the difference of the squares of the other two numbers by 60.

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There are three consecutive integers (same as, natural
numbers).

let the smallest of the numbers be
.

Values of
:

1st no. is
2nd no. is .
3rd no. is   .

Condition: The square of the 2nd no. (middle number) is 60 more than the difference of the squares of other two numbers.

Solution:

=>

=>

=>

=>

=>

=>

By putting the values of ,

1st no. is .
2nd no. is .
3rd no. is .

ANSWER: ﻿The values of the three consecutive numbers:

1st no. is .
2nd no. is .
3rd no. is .

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