# 2 eqial sides of a triangle are 5 cm less than ots 3rd sodw if perimeter of teiangle is 55 m find length of each sides

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let the otherside be c

length of 1 of the equal sides =c-5

perimeter of the triangle =a+b+c=55m

=c-5+c-5+c=55m

=3c-10=55m

=c=55-10/3

=c= 45/3= 15m

a =c-5=15-5=10m

b=a=10m

c=15m

The Brainliest Answer!

a+b+c=55m

a.t.q., c-5+c-5+c=55

3c-10=55

3c=55+10

3c=65

c=65÷3

c=21.66.........

c=22m

now,if c=22m

then a and b =22-5=17m

please mark as brainliest answer and click thanks.