Answers

2016-01-03T11:58:50+05:30
Molecular mass of sucrose=342 u
molar mass = 342 g
given mass =3.42 g
given mass in terms of molar mass = 1/100 of molar mass
No. of molecules in 1 mole =6.022*10^23
No. of molecules in given mass = 1/100 * 6.022*10^23=6.022*10^21
No.of oxygen atoms in 1 molecule of sucrose =11
No.of oxygen atoms in 6.022*10^21 molecules =11*6.022*10^21=6.6242*10^22atoms
Now,given water 18g
molecular mass of water = 18 u
given water = 18g = 1 mole
no.of oxygen atoms in 1 molecule of water = 1
No. of oxygen atoms in 6.022*10^23 molecules =1*6.022*10^23=6.022*10^23 atoms
Total no. of oxygen atoms inthe solution =6.022*10^23+0.66242*10^23
=6.68442*10^23 atoms
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