# 1 pipe can fill a cistern in 3 hours less than the other . the 2 pipes together can fill the cistern in 6 hours 40 minutes. find the time that each pipe will take to fill the cistern

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time taken by 2nd pipe be y

given y=x-3hrs= x-180min.

if they together will fill it then they willdo half of their work.

x+y/2= 6h+40m=400min.

x+x-180/2=400min.

x-90=400

x=490min.

x=8hrs and 10min.

y= x-3hrs= 8hrs 10min.-3hrs.

y= 5hrs 10min.

Please mark as brainliest answer......and press thank you

**time taken by both of them =6hr40min**

**average time takenby each =6hr40min*2**

**=400min *2=800min**

**3hr=180min **

**so time takenby by first person =800-90=710min=11hr50min **

**timen taken by second person =800+90min=890min=14hr50min**

**if helps pls mar it best**