# A person invests rs.10000 at 10% compound interest for two years.then he invests the maturity amount for one year at 10% cpmpound interest for compounded half yearly.what total amount he receive at the end of three years

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A = P(1+r/n)^nt

A is amount to be received

P is principal

r is rate of interest

n is no. of times compounded in 1 year

t is no.of years

A = P (1+r/n)^nt

A = 10000(1+0.1/1)^1*2

=10000*(1.1)^2

= 10000*(1.21)

= 12100

Now, P is 12100

A= P(1+r/n)^nt

= 12100(1+0.1/2)^2*3

= 12100(2.1/2)^6

= 12100(85.766121/64)

= 12100(1.34009564)

= 16215.1572

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