Answers

2016-01-05T06:57:46+05:30
Let tens digit be y and once digit be x

so tens digit = 10y
once digit = x

Original number = 10y + x

Now after interchanging the digit the new no. become = 10x + y

A.T.Q

(10y +x) - (10x +y) = 36
10y + x - 10x - y = 36
9y-9x = 36

9(y-x) = 36

y-x = 36/9

y-x = 4
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2016-01-05T07:37:48+05:30
Let the ones digit and tenth digit be x and y respectively.
Therefore ,the required number =10y+x
As per problem,
10y+x-(10x+y)=36
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