PQRS is a rhombus with diagonals PS and QS.PR = 16 cm and QS = 12 cmA, B, C and D are the mid points of sides PQ, PS, RS and QR respectively.We know, that the figure obtained on joining the mid points of a rhombus is rectangle.∴ ABCD is a rectangle.Consider ΔPQS, A and B are the mid point of PQ and PS respectively.∴ By mid point theorem, AB || QS andSimilarly in ΔPQR, AD || PR andThus, area of rectangle ABCD = AB × CD= (6 × 8) cm2= 48 cm2