Answers

2016-01-06T20:53:49+05:30
Let A (3,10); B(5,2);C(14,12)
area of triangle ABC = 1/2 [ x1(y2-y3)+x2(y3-y1)+x3(y1-y2)
                                  = 1/2 [ 3(2-12)+5(12-10)+14(10-2)]
                                  = 1/2 [3 (-10)+5(2)+14(8)]
                                  = 1/2 [-30+10+112]
                                  = 1/2 [92]
                                  = 46 sq. units
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perimeter has been asked not area
sorry i didnt see