# The far point of a myopic person is 80 cm in front of the eye.what is the nature and power of the lens require to correct the problem?

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by anmol6

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by anmol6

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to correct far point should be infinity, v =infinity

applying lens law,

1/v -1/u = 1/f

⇒ 0 - 1/0.8 = 1/f

⇒1/f = (-1/0.8)= - 1.25

now, power of lens = 1/f

= -1.25D

So