# The base and height of a ∆ are in the ratio 3:2 and it's area is 108cm? Find it's base and height.

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by kakkar6644

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by kakkar6644

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The Brainliest Answer!

Let us assume that base = 3x cm and height = 2x cm

Given area of the Δ = 108 cm²

⇒1/2 ×3x × 2x = 108

⇒1/2 × 6x² = 108

⇒ 6x² /2 = 108

⇒ 3x² = 108

⇒ x² = 108/3

⇒ x² = 36

⇒ x = √36 or x = -√36

⇒ x = 6 or x = -6

∵ dimensions can not be negative x = 6

∴Base = 3x = 3(6) = 18 cm

Height = 2x = 2(6) = 12 cm

1/2 x 3x x 2x = 108

1 x 3x x x = 108

3x^2 = 108

x^2 = 36

x = 6

Base = 18

Height = 6