# If centre of a circle is X(2, -3) and end of diameter is A(3,5),then find the coordinates of other end B

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by thanvi

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by thanvi

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x is center of circle and ab is diameter....hence x bisects AB

Now there are 2 ways to do this...

Take the coordinate of B as (x,y) and use AX = BX in distance formula and equate or you could do section formula for midpoint

If u do everything right u should get B = (1,-11)

We know that the centre of a circle divides the diameter in half.

Now we take the other pt on the diameter as (a,b)

so, by the distance formula,

from here we get

and

hope that it was helpful, if it was pls do let me know