# Ab and dc are parallel sides of the trapezium abcd and angle adc = 90 degrees. given ab= 15 cm,cd=40 cm and diagonal ac= 41 cm, calculate the area of trapezium abcd.

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by preet2002

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by preet2002

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The Brainliest Answer!

Ab parallel to dc

ab = 15 cm

cd = 40cm

ac = 41 cm

Using Pythagoras Theorem

ad² + dc² = ac²

ad² + 40² = 41²

ad² + 1600 = 1681

ad = √1681- 1600

ad = √81

as = 9 cm

area of trapezium =1/2 × (base1 + base2) × h

1/2× ( 15 + 41) × 9

= 247.5 cm²

In right angled ΔADC,

AD = √(41^2-40^2)= 9

area=(1/2)(15+40)(9)=247•5cm^2

AD = √(41^2-40^2)= 9

area=(1/2)(15+40)(9)=247•5cm^2