# Two parallel sides of an isosceles trapezium are 6 cm and 14 cm respectively. if the length of each non parallel side is 5 cm, find the area of the trapezium.

2
by preet2002

Log in to add a comment

by preet2002

Log in to add a comment

rectangle having one side =6 cm

triangle's sides are 5cm and 4cm

To find the third side or the perpendicular distance between both parallel lines,

Apply pythagoras' theorem.

height =√((5)² -(4)²)

= 3 cm

so,

= (1/2)×(6+ 14)×3

= 30 cm²

The Brainliest Answer!

Now,

AB=6 cm

CD=14 cm

AD=BC=5 cm

Construct a line parallel to BC from A to a point E on DC.

NOw, ar(ADE)= 12 sq. cm (By Heron's Formula)

ar(ADE)= 1/2*b*h

Therefore the height is 6 cm.

ar(ABCE)= b*h

=6cm*6cm

=36 sq.cm

Hence, area of ABCD is=12+36 i.e. 48 sq. cm.