Answers

2016-01-15T12:05:41+05:30

10/3x+21/5x+49/8x=4917.........(1)
x[10/3+21/5+49/8]=4917
x[10*5*8+21*3*8+49*3*5]
= 4917*3*5*8
x[400+504+734]=4917*3*5*8
x[1639]=590040
x=590040/1639=360
x=360.
put the value of x into equation (1) and we get,
10/3x=1200,
21/5x=1512,
49/8x=2205.
we get the three numbers are 1200, 1512, and 2205.




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2016-01-15T12:09:06+05:30
31x/3 + 41x/5 + 61x/8 = 4917

1240x + 984x +915x/120 = 4917

1240x + 984x +915x = 4917 × 120
1240x + 984x +915x   =590040
3140x = 590040
x = 187.91
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