# How many tiles with dimention 5 n 12 cm will be needed to fit a region whose length n breadth is (a)100 n 144 cm (b)70 n 36 cm?

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by Arushi654

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by Arushi654

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Given length of tile = 12cm

Breadth = 5cm

Length of the region = 144cm

breadth = 100cm

No.of tiles needed to cover = Area of region/Area of 1 tile

= (144 × 100)/(5 × 12)

= 14400/60

= 240

∴No.of tiles required to cover a region of dimensions 100 cm and 144cm is 240

b) length of the region = 70cm

breadth of the region = 36cm

No.of tiles = Area of the region / Area of 1 tile

= (70 × 36)/(5 × 12)

= 2520/60

= 42

∴No.of tiles required to cover the region of dimensions 70cm and 36cm is 42

Breadth = 5cm

Length of the region = 144cm

breadth = 100cm

No.of tiles needed to cover = Area of region/Area of 1 tile

= (144 × 100)/(5 × 12)

= 14400/60

= 240

∴No.of tiles required to cover a region of dimensions 100 cm and 144cm is 240

b) length of the region = 70cm

breadth of the region = 36cm

No.of tiles = Area of the region / Area of 1 tile

= (70 × 36)/(5 × 12)

= 2520/60

= 42

∴No.of tiles required to cover the region of dimensions 70cm and 36cm is 42