Answers

2014-02-21T22:37:32+05:30
Let the vol.of copper be 3V
yhen vol. of irom=V
let the wt. of iron be x
then wt of  copper=285.5+x
given
density of copper=8.9g\cu m
density of iron =7.8g\cu m
now density =mass÷volume

so, 8.9=(285.5+x)÷3V                                   1-eq
now,simlarily
7.8=x÷V
or 7.8V=x 
now put the value of x in eq-1
then you will get V=10.98cu m
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