# The sum of three terms of an arithmetic progression is 21 their products of first and the third terms exceed the second term by 6.find the numbers

2
by harsathraina

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by harsathraina

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From question,

+ + = 21

a - d + a + a + d = 21

3a = 21

a = 7

Now,

x = + 6

(a - d)(a + d) = a + 6

(7 - d) (7 + d) = 7 + 6

- = 13

49 - = 13

- = 13 - 49

- = - 36

= 36

d =

d = 6.

Now,

= a - d = 7 - 6 = 1

= a = 7

= a + d. = 7 + 6 = 13

∴ = 1

= 7

= 13

Please comment if answer is satisfying/