# Find the number of coins of 1.5 cm diameter and 0.2 cm thickness to be melted to form a right circular cylinder of height 10 cm and diameter 4.5 cm.

2
by sou5mys2olkosvichukl

2016-01-26T00:57:37+05:30
Each one of those coins is also a cylinder (just a very very short one), and its volume is
V = πr²h = π(.75)²(.2) = 9π/80 cm³
The right circular cylinder has volume V = π(2.25)²(10) = 405π/8 cm³.

Divide the larger cylinder's volume by the volume of each coin = (405π/8) / (9π/80) = 450 coins
• qais
• Content Quality
2016-01-26T10:20:30+05:30

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As the coins are in the form of thin cylinder
Volume of each coin = π×(0.75)²×0.2 =0.1125π cm³
Volume of melted cylinder = π× (2.25)²× 10 = 50.625π cm³
number of coin required = (volume of melted cylinder)/(volume of each coin)
= 50.625π/0.1125π = 450 coins