# ABC is an isocles triangle with ac =bc and ab^2=2ac^2 .prove that abc is right angled triangle. pllzzzzzzz rply fstttt

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by shravs1

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by shravs1

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It is given in the question that AC=BC and AB^2=2AC^2

Now ,in a right angled triangle ,

hypotenuse^2=base^2 +altitude^2

So according to the theorem in this case,

AB^2=AC^2+BC^2

In the question it is clearly mentioned that AC=BC

ie;AB^2=AC^2+AC^2

ie;AB^2=2AC^2

Hence proved

so ac^2+bc^2 = ac^2+ac^2 = 2(ac)^2

acc to pythagorous thm

ab^2= ac^2 + bc^2 = 2(ac)^2

hence verified