# Derive f=ma and expain newton second law

2
by zak3

2016-01-27T12:58:57+05:30
Newton's 2nd law of motion :
The law states that the rate of change of momentum of a body is proportonal to the Force
producing it and takes place in the direction in which the force acts.
Momentum of a body = P = mass* velocity = mV (Vector quantity) ; V = Velocity
Let m = mass of the body
Initial velocity = u ; initial momentum = mu (Vector)
Final velocity = v ; final velocity = mv (vector)
Time interval = t
Change in velocity = m(v - u) (vector)
Rate of change of momementum = m(v - u) / t = m{(v- u)/t} = ma (vector) ; a = acceleration (vector)
plsm amrk as brainliest ans
mark as brainliest ans
2016-01-27T15:52:24+05:30
Second law of newton : the rate of change of momentum of a body is directly proportional to the net force acting on it and it take place in the direction of net force

according to newton's second law
appiled force= f
mass=m
intial velocity =u
final velocity= v
time= t
intial momentum (p) =mu
final momentum (p) =mv
change in momentum (delta P) =mv-mu
rate of change in momentum = (delta p/t)
=mv-mu/t
m(v-u)/t
=ma(∴a=v-u/t)
=according to 2nd law
f alfa ma
=f=kma
where k= proportional constant
k=1
f=1×ma
=f=ma
it's an easy method of understanding i hope u understand