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2016-01-27T18:04:12+05:30

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Let the shorter side be x
diagonal will be (16 +x) m
length = (14+x)
By Pythagors' theorem,
(16 +x)² = x² + (14 +x)²
⇒256 +x² +32 x = x² + 196 +x² + 28x
⇒x² -4x -60 =0 
⇒x² - 10x + 6x - 60 =0
⇒x (x-10) +6(x -10)=0
⇒x = 10 or -6
negative side is impossible
so length of smaller side = 10 m
longer side = 24 m
diagonal = 26 m
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2016-01-27T18:37:34+05:30
Let shorter side be x
.'. diagonal is x+16
side 2=x+14
(x+14)²+x²=(x+16)²   by pythogras therom
x²+196+28x+x²=x²+256+32x
x² -4x -60 =0 
x² - 10x + 6x - 60 =0
 (x-10) +6(x -10)=0
x = 10 or -6
negative side is not possible
so length of smaller side = x=10 m
longer side =x+14=  24 m
diagonal = x+16=26 m
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