# Rate of 1choclate=5paisa. rate of 1 banana=1rupees.rate of 1 coconut= 5rupees. make hundred pices with hundred rupees. how many picees choclate,banana,coconut

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by chandaamitav

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by chandaamitav

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therefore x+y+z=100----------------eqn(1)

1 banana=1 rupees , 1chocolate=5/100=1/20 rupees , 1 coconut=5 rupees

a/q, 1/20x+y+5z=100

or, x+20y+100z=2000-------------eqn(2)

or, (100-y-z)+20y+100z=2000 ----------------------from eqn(1)

or, 99z+19y=1900

or, 80z+19z+19y=1900

or, 80z+19(y+z)=1900

or, 80z+19(100-x)=1900

or, 80z-19x=0

x/z=80/19

so, when x=80,then z=19

it means when x is less than 80 then z will be in fraction which is not possible ,because x,y,z are numbers of things .or if x is greater than 80 then z will be in fraction.

therefore x =80 ,z=19,y=1

no. of banana = y

no. of coconut =z

therefore x+y+z=100----------------(1)

1 banana=1 rupees

1chocolate=5/100=1/20 rupees

1 coconut=5 rupees

1/20x+y+5z=100

⇒ x+20y+100z=2000-------------eqn(2)

⇒ (100-y-z)+20y+100z=2000 ----------------------from eqn(1)

⇒ 99z+19y=1900

⇒ 80z+19z+19y=1900

⇒ 80z+19(y+z)=1900

⇒ 80z+19(100-x)=1900

⇒ 80z-19x=0

x/z=80/19

therefore when x=80,then z=19

⇒ when x is less than 80 then z will be in fraction which is not possible

⇒x≠80

since because x,y,z can take only numeric values

therefore x =80 ,z=19,y=1