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## Answers

(7)^2x-4 = 1

Multiply both sides by 7

[(7)^2x-4] × 7 = 1 × 7

⇒ 7^ (2x-4+1) = 7^1 [ a^n × a^m = a^(n+m)]

⇒ 7^ (2x-3) = 7^1

⇒ 2x-3 = 1 [∵ Bases are same power are equal]

⇒ 2x = 1+3

⇒ 2x = 4

⇒ x = 4/2

∴ x = 2

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(7)^2x-4 = 1

Multiply both sides by 7

[(7)^2x-4] × 7 = 1 × 7

⇒ 7^ (2x-4+1) = 7^1 [ a^n × a^m = a^(n+m)]

⇒ 7^ (2x-3) = 7^1

⇒ 2x-3 = 1 [∵ Bases are same power are equal]

⇒ 2x = 1+3

⇒ 2x = 4

⇒ x = 4/2

∴ x = 2