# In triangle ABC D,E,F ARE MID POINTS OF SIDES AB, BC AND CA show that abc is divided into 4 congruent triangles

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by vishakha

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by vishakha

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The Brainliest Answer!

so, AD=DB, AE=EC, BF=FC

if you draw a figure you will find that line segment DF is parallel to the line EC.

so EC=DF and similarly EF=AD then DE=FC also

the theorem proved by the definition of conjugate triangles.

Therefore, AD=DB, AE=EC, BF=FC

line segment DF // EC.

so EC=DF

similarly EF=AD

DE=FC also

the theorem proved by the definition of conjugate triangles.