# From the top of the hundred metre high building than that of depression of a car on the road is 30° then find the distance of the car from the building

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by Shaurya05

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by Shaurya05

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angle of dep. 30'

Car at C

angle ACB +30' (alternate angles)

tan 30 +1/root(3) = AB/BC= 100/BC

BC =100*root(3)

Height of tower = 100 m

It will make a triangle if you take an point to represent car.

Rotate your figure to left side.

30 degrees will shift to down & 100m will be base.

let the distance between building and car be x m.

therefore

tan 30 degrees=x m/100m

Simply it, you will get 57.74 m as the answer.