# A certain sum if money compounded annually becomes Rs6750 after 1year and Rs 7873.20 after 3years.find the sum.

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Let the sum of Rs x

As,**A =P (1 +R/100)^t**

⇒6750 = x(1+R/100)

⇒(1+R/100)= 6750/x______(1)

After 1 years Rs 6750 will become the sum for the amount Rs 7873.20 for 2 years

so, A =P (1 +R/100)^t

⇒7873.20 = 6750 (1 +R/100)²

now putting the value of (1),

7873.20 = 6750 ×(6750/x)²

⇒x² =( 6750)³/7873.20

= 39062500

⇒x =√39062500

⇒**x =Rs 6250**

Rate can be determined from the equation (1), by substituting this value.

(1+R/100) = 6750/6250

⇒R/100 = 2/25

⇒R = 8%

As,

⇒6750 = x(1+R/100)

⇒(1+R/100)= 6750/x______(1)

After 1 years Rs 6750 will become the sum for the amount Rs 7873.20 for 2 years

so, A =P (1 +R/100)^t

⇒7873.20 = 6750 (1 +R/100)²

now putting the value of (1),

7873.20 = 6750 ×(6750/x)²

⇒x² =( 6750)³/7873.20

= 39062500

⇒x =√39062500

⇒

Rate can be determined from the equation (1), by substituting this value.

(1+R/100) = 6750/6250

⇒R/100 = 2/25

⇒R = 8%