# A constant force of magnitude 10 N is applied to a body of mass 2 kg at a displacement of 4 m on a horizontal floor flat. Knowing that the body was at rest, calculate: a) The kinetic energy of the body b) the final velocity of the body

2
by Castieldoidao

2014-07-19T10:02:21+05:30

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Force(F) = 10 N , Mass(m) = 2 kg , Distance(d or s) = 4 m

a) Kinetic Energy = Work done = Force × Displacement
Kinetic Energy = F×d
Kinetic Energy (K.E.) = (10 × 4) = 40 Joules

b) Now we have Kinetic Energy = 40 Joules
Formula of K.E. = ×mv²
Now put the values,
We get,
40=
v²=40
v=√40
v=6.32m/s
The final velocity is 6.32m/s

2014-07-22T19:10:00+05:30

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Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
F = 10 N    => acceleration a = 10 N / 2 kg = 5 m/s^2
u = 0 initial.
v^2 - u^2 = 2 a s      => v^2 = 2 * 5 * 4 = 40
so,    v = sq root of 40.

KE = 1/2 * 2 kg * 40 = 40 Joules